4t^2(t+3(1+4ln(t)))=0

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Solution for 4t^2(t+3(1+4ln(t)))=0 equation:


Simplifying
4t2(t + 3(1 + 4ln(t))) = 0

Multiply ln * t
4t2(t + 3(1 + 4lnt)) = 0
4t2(t + (1 * 3 + 4lnt * 3)) = 0
4t2(t + (3 + 12lnt)) = 0

Reorder the terms:
4t2(3 + 12lnt + t) = 0
(3 * 4t2 + 12lnt * 4t2 + t * 4t2) = 0

Reorder the terms:
(48lnt3 + 12t2 + 4t3) = 0
(48lnt3 + 12t2 + 4t3) = 0

Solving
48lnt3 + 12t2 + 4t3 = 0

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Add '-12t2' to each side of the equation.
48lnt3 + 12t2 + -12t2 + 4t3 = 0 + -12t2

Combine like terms: 12t2 + -12t2 = 0
48lnt3 + 0 + 4t3 = 0 + -12t2
48lnt3 + 4t3 = 0 + -12t2
Remove the zero:
48lnt3 + 4t3 = -12t2

Add '-4t3' to each side of the equation.
48lnt3 + 4t3 + -4t3 = -12t2 + -4t3

Combine like terms: 4t3 + -4t3 = 0
48lnt3 + 0 = -12t2 + -4t3
48lnt3 = -12t2 + -4t3

Divide each side by '48nt3'.
l = -0.25n-1t-1 + -0.08333333333n-1

Simplifying
l = -0.25n-1t-1 + -0.08333333333n-1

Reorder the terms:
l = -0.08333333333n-1 + -0.25n-1t-1

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